A basket contains 4 red, 5 blue and 3 green marbles. If three marbles are picked at random, what is the probability that atleast one is blue?
Correct Answer: Description for Correct answer:
Total number of possible outcomes = \( 12C_3 = 220 \)
Number of events which do not contain blue marbles(3 marbles out of 7 marbles)
= \( 7C_3 = 35 \)
Required probability = 1 - \( \large\frac{35}{220} = \frac{37}{44} \)
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