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A basket contains 3 blue, 2 green and 5 red balls. If four balls are picked at random, what is the probability that two are green and two are blue?

A) 1 / 18
B) 1 / 70
C) 3 / 5
D) 1 / 2

Correct Answer:


B) 1 / 70

Description for Correct answer:
Total number of outcomes = \( 10C_4 \) = 210
Favourable number of outcomes = \( 3C_2 \times 2C_2\) = 3 x 1= 3
Required probability =\( \large\frac{3}{210} = \frac{1}{70} \)

Part of solved Probability questions and answers : >> Aptitude >> Probability

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