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A basket contains 4 red, 5 blue and 3 green marbles. If three marbles are picked at random, what is the probability that either all are green or all are red?


A) 7 / 44

B) 7 / 12

C) 5 / 12

D) 1 / 44

Correct Answer:
D) 1 / 44

Description for Correct answer:
Total number of ways of selection 3 marbles out of 12 = n(S) = \( 12C_3 \) = 220
Total number of favourable events
= n(E) =\( 3C_3 + 4C_3 \) = 1 + 4 = 5
Required probability = \( \large\frac{5}{220} = \frac{1}{44} \)

Part of solved Probability questions and answers : >> Aptitude >> Probability




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