Topics
Find the area of a rhombus whose one side is 13 cm. and the diagonal is 24 cm.
Correct Answer:
Description for Correct answer:
Area of rhombus = \( \Large \frac{1}{2} \times d_{1} \times d_{2} \)
To find the length of the diagonal AC.
\( \Large \triangle OAB,\ \angle AOB=90 ^{\circ} \); OB = 12 cm; AB = 13 cm.
\( \Large AO^{2}=AB-OB^{2}=13^{2}-12^{2}=25 \)
AO =\( \Large \sqrt{25} \)= 5 cm
Therefore, length of one diagonal is 10 cm and the length of another diagonal is 24 cm.
Therefore, Area of Rhombus = \( \Large \frac{1}{2} \times d_{1} \times d_{2}=\frac{1}{2} \times 10 \times 24 \) = 120 sq. cm.
Area of rhombus = \( \Large \frac{1}{2} \times d_{1} \times d_{2} \)
To find the length of the diagonal AC.
\( \Large \triangle OAB,\ \angle AOB=90 ^{\circ} \); OB = 12 cm; AB = 13 cm.
\( \Large AO^{2}=AB-OB^{2}=13^{2}-12^{2}=25 \)
AO =\( \Large \sqrt{25} \)= 5 cm
Therefore, length of one diagonal is 10 cm and the length of another diagonal is 24 cm.
Therefore, Area of Rhombus = \( \Large \frac{1}{2} \times d_{1} \times d_{2}=\frac{1}{2} \times 10 \times 24 \) = 120 sq. cm.
Part of solved Area and perimeter questions and answers : >> Elementary Mathematics >> Area and perimeter
Comments
Similar Questions
