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Find the area of right angled triangle if its base is 3 cms. and hypotenuse is 5 cm.
Correct Answer:
Description for Correct answer:
From the Triangle ABC find AB.
\( \Large AC^{2}=AB^{2}+BC^{2} \)
\( \Large 5^{2}=AB^{2}+BC^{2} \)
\( \Large AB^{2}=5^{2}-BC^{2}=5^{2}-3^{2}=25-9=16 \)
\( \Large AB=\sqrt{16} \) = 4 cm.
Area of the triangle = \( \Large \frac{1}{2}bh \)
=\( \Large \frac{1}{2} \times 3 \times 4 \)= 6 sq. cm.
From the Triangle ABC find AB.
\( \Large AC^{2}=AB^{2}+BC^{2} \)
\( \Large 5^{2}=AB^{2}+BC^{2} \)
\( \Large AB^{2}=5^{2}-BC^{2}=5^{2}-3^{2}=25-9=16 \)
\( \Large AB=\sqrt{16} \) = 4 cm.
Area of the triangle = \( \Large \frac{1}{2}bh \)
=\( \Large \frac{1}{2} \times 3 \times 4 \)= 6 sq. cm.
Part of solved Area and perimeter questions and answers : >> Elementary Mathematics >> Area and perimeter
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