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A) 28.642 sq. cm. |

B) 26.832 sq. cm. |

C) 24.564 sq. cm. |

D) 22.832 sq. cm. |

Correct Answer:

B) 26.832 sq. cm. |

Description for Correct answer:

Area of the triangle = \( \Large \sqrt{s \left(s-a\right) \left(s-b\right) \left(s-c\right) } \)

\( \Large s = \frac{a+b+c}{2} \)

\( \Large s = \frac{7+8+9}{2}=\frac{24}{2} \)= 12 cm.

Area of the triagle =\( \Large \sqrt{12 \left(12-7\right) \left(12-8\right) \left(12-9\right) } \)

=\( \Large \sqrt{12 \times 5 \times 4 \times 3} = \sqrt{36 \times 4 \times 5} = 6 \times 2\sqrt{5} \)

=\( \Large 6 \times 2.236=12 \times 2.236=26.832 sq. cm. \)

Area of the triangle = \( \Large \sqrt{s \left(s-a\right) \left(s-b\right) \left(s-c\right) } \)

\( \Large s = \frac{a+b+c}{2} \)

\( \Large s = \frac{7+8+9}{2}=\frac{24}{2} \)= 12 cm.

Area of the triagle =\( \Large \sqrt{12 \left(12-7\right) \left(12-8\right) \left(12-9\right) } \)

=\( \Large \sqrt{12 \times 5 \times 4 \times 3} = \sqrt{36 \times 4 \times 5} = 6 \times 2\sqrt{5} \)

=\( \Large 6 \times 2.236=12 \times 2.236=26.832 sq. cm. \)

Part of solved Area and perimeter questions and answers : >> Elementary Mathematics >> Area and perimeter

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