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Find the area of a rectangle whose one side is 9 mts. and the length of the diagonal is 15 mts.
Correct Answer:
Description for Correct answer:
From triangle ABC
\( \Large AC^{2}=AB^{2}+BC^{2} \)
\( \Large AB^{2}=AC^{2}-BC^{2} \)
=\( \Large 15^{2}-9^{2}= \left(15+9\right) \left(15-9\right) \)
=\( \Large 24 \times 6 = 144 \)
\( \Large AB = \sqrt{144} = 12 mts. \)
Area = \( \Large 12 \times 9 = 108 m^{2} \)
From triangle ABC
\( \Large AC^{2}=AB^{2}+BC^{2} \)
\( \Large AB^{2}=AC^{2}-BC^{2} \)
=\( \Large 15^{2}-9^{2}= \left(15+9\right) \left(15-9\right) \)
=\( \Large 24 \times 6 = 144 \)
\( \Large AB = \sqrt{144} = 12 mts. \)
Area = \( \Large 12 \times 9 = 108 m^{2} \)
Part of solved Area and perimeter questions and answers : >> Elementary Mathematics >> Area and perimeter
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