A) 4 |
B) 9 |
C) 10 |
D) none of these |
C) 10 |
\( \Large 4^{log_{3}\frac{31}{2}} + 9^{log_{2}2^{2}} = 10^{log_{x}83} \)
=> \( \Large 4^{\frac{1}{2}} + 9^{2} = 10^{log}x^{83} \)
=> \( \Large 2 + 81 = 10^{log}x^{83} \)
=> \( \Large 83 = 10^{log}x^{83} \)
=> x = 10