A) 20 m |
B) 40 m |
C) 30 m |
D) 60 m |
A) 20 m |
Let the height of the tree be h and breadth of the river be b.
\( \Large In \triangle DBC, \tan 60 ^{\circ} = \frac{h}{b} \)
=> \( \Large h = b\sqrt{3} \) ...(i)
=> \( \Large In \triangle DAC, \tan 30 ^{\circ} = \frac{h}{40+b} \)
=> \( \Large h = \frac{40+b}{\sqrt{3}} \) ...(ii)
From Eqs. (i) and (ii), we get
\( \Large b\sqrt{3} = \frac{40+b}{\sqrt{3}} \)
=> \( \Large 2b = 40 => b = 20 m \)