Which of the following is not true?


A) \( \Large \frac{1}{log_{3} \pi } + \frac{1}{log_{4} \pi }>2 \)

B) \( \Large log_{3}5 \)

C) \( \Large \sqrt{8x} = \frac{10}{3} => x = 16 \)

D) \( \Large log_{x} \left(a^{2}+1\right)<0 \), (a?0) then 0

Correct Answer:
C) \( \Large \sqrt{8x} = \frac{10}{3} => x = 16 \)

Description for Correct answer:

(A) \( \Large \frac{1}{log_{3} \pi } + \frac{1}{log_{4} \pi } = log_{ \pi }3 + log_{ \pi }4 = log_{ \pi}  12 > 2\)

\( \Large 12 > \pi ^{2} \)

(B) \( \Large log_{3}5 \) is an irrational number

(C) \( \Large log\sqrt{8}x = \frac{10}{3} => x = \left(\sqrt{8}\right)^{\frac{10}{3}} = 2^{5} \)

\( \Large x = 32 \)

(D) \( \Large log_{x} \left(a^{2}+1\right) < 0, a ≠ 0 => a^{2}+1 > 1 \)

So, log is negative

Hence, base is (0, 1).


Part of solved Logarithms questions and answers : >> Elementary Mathematics >> Logarithms








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