A) 4 |
B) 9 |
C) 16 |
D) 32 |
C) 16 |
\( \Large log^{2}xy \ge 6 => xy \ge 2^{6} \)
Now \( \Large \frac{x + y}{2} \ge \sqrt{xy} \)
\( \Large Now \frac{x+y}{2} \ge 2^{3} => x+y \ge 2^{4} => x+y \ge 16 \)