A) a = b |
B) a = b/2 |
C) 2a = b |
D) \( \Large a = \frac{b}{3} \) |
A) a = b |
\( \Large log \left(\frac{a+b}{2}\right) = \frac{1}{2} \left(log_{e}a + log_{e}b\right) \)
=> \( \Large \frac{a+b}{2} = \sqrt{ab} \)
=> \( \Large a+b-2\sqrt{ab} = 0 \)
=> \( \Large \sqrt{a} = \sqrt{b} => a = b \)