A) 1 |
B) 0 |
C) 2 |
D) 3 |
D) 3 |
By definition x ≠ 1, =1
Given equation can be written as
\( \Large log \frac{ \left(x+1\right)^{2} }{x^{2}-1} = log2 => \frac{x+1}{x-1}=2 => x = 3\)