What are the dimensions (length, breadth and height, respectively) of a cuboid with volume 720 cu cm, surface area 484 sq cm and the area of the base 72 sq cm?

Volume of the cuboid = \( \Large 720 cm^{3} \)

Height of the cuboid

= \( \Large \frac{Volume \ of \ the \ cuboid}{Base \ area \ of \ the \ cuboid} \)

= = \( \Large \frac{720}{72} = 10 cm \)

Surface area of the cuboid

= \( \Large 2 \left(lb + bh + hl\right) \)

= \( \Large 2 \left(9 \times 8 + 8 \times 10 + 10 \times 9\right) \)

= \( \Large 2 \left(72 + 80 + 90\right) \)

=\( \Large 2 \times 242 \)

= \( \Large 484 cm^{2} \)

Therefore, It is obvious that length, breadth and height of the cuboid is 9 cm, 8 cm and 10 cm.