A) \( \Large 12 cm^{2} < x < 15 cm^{2} \) |
B) \( \Large 15 cm^{2} < x < 17 cm^{2} \) |
C) \( \Large 17 cm^{2} < x < 19 cm^{2} \) |
D) \( \Large 19 cm^{2} < x < 21 cm^{2} \) |
A) \( \Large 12 cm^{2} < x < 15 cm^{2} \) |
OB = OA = radius
Also, \( \Large \angle AOB = 60 degree \ \left(\frac{360 \ degree}{6}=60 \ degree\right) \)
and \( \Large \angle OAB=\angle OBA = 60 degree \)
\( \Large \triangle AOB \)is an equilateral triangle.
Then, AB = 5 cm
so, area x = Area of circle - Area of hexagon
=\( \Large \pi r^{2}-\frac{3\sqrt{3}(a)^{2}}{2} \)
=\( \Large \frac{22}{7}\times (5)^{2}-\frac{3\sqrt{3}}{2}\times (5)^{2} \)
=78.57-64.95=\( \Large 13.62 cm^{2} \)