A) 1331 \( \Large cm^{3} \) |
B) 1232 \( \Large cm^{3} \) |
C) 1626 \( \Large cm^{3} \) |
D) 1836 \( \Large cm^{3} \) |
A) 1331 \( \Large cm^{3} \) |
According to the question,
\( \Large 6a^{2} = 726 \) [a = edge of the cube]
=>\( \Large a^{2} = \frac{726}{6} = 121 \)
Therefore, \( \Large a = \sqrt{121} = 11 cm \)
Therefore, Required volume =
\( \Large a^{3} = 11^{3} = 1331 cm^{3} \)