A cube has each edge 2 cm and a cuboid is 1 cm long, 2 cm wide and 3 cm high. The paint in a certain container is sufficient to paint an area equal to 54 \( \Large cm^{2} \). Which one of the following is correct?

Surface area of cube which can be painted = \( \Large 6 \left(Side\right)^{2} = 6 \left(2\right)^{2} = 2 cm^{2} \)

Now. surface area of cuboid which can be painted

\( \Large 2 \times \left(lb+bh+lh\right) \)

\( \Large 2 \left(2+6+3\right) = 22 cm^{2} \)

Total surface area of both cube and cuboid

= \( \Large 22 + 24 = 46 cm^{2} < 54 cm^{2} \)

Therefore, both cube and cuboid can be painted.