A) Area of circle = Area of square |
B) \( \Large Area \ of \ circle \ge \ Area \ of \ square \) |
C) Area of circle > Area of square |
D) Area of circle < Area of square |
C) Area of circle > Area of square |
Let the radius of a circle is r and a be the length of the side of a square.
Given, circumference of a circle = Perimeter of a square
=> \( \Large 2\pi r \)=4a
=> a=\( \Large \frac{\pi }{2}r \)=1.57r
Now, area of the circle \( \Large (A_{c}) \)=\( \Large \pi r^{2}=3.14 r^{2} \)
and area of the square
\( \Large (A_{s})=a^{2}=2.4649 r^{2} \)
Area of circle > Area of square.