Given that,
Area of \( \Large \triangle BFC \) = \( \Large 6 cm^{2} \)
\( \Large \frac{1}{2} \times 3 \times x\times \) =6 =>x=4cm
In \( \Large \triangle BFC, BF^{2}=4^{2}+3^{2}=16+9 \)
=> \( \Large BF^{2}=25 \)
=> BF=5
Area of rectangle ABCD \( \Large pq^{2} \)=\( \Large p(2)^{2} cm^{2} \)
Which is of the form \( \Large pq^{2} \).
While the area of EBFD cannot be the form of \( \Large r^{2} cm^{2} \)