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A chocolate has 12 equal pieces. Manju gave \( \Large \frac{1}{4} \)th of it to Anju, \( \Large \frac{1}{3} \)rd of it to Sujata and \( \Large \frac{1}{6} \)th of it to Fiza. The number of pieces of chocolate left with Manju is

Correct Answer:

A) 1 |
B) 2 |

C) 3 |
D) 4 |

Correct Answer:

C) 3 |

Description for Correct answer:

The number of pieces of chocolate with Maniu

= \( \Large 1 - \left(\frac{1}{4}+\frac{1}{3}+\frac{1}{6}\right) \)

= \( \Large 1 - \left(\frac{3 + 4 + 2}{12}\right) \)

= \( \Large 1 - \frac{9}{12} = \frac{12 - 9}{12} = \frac{3}{12} \)

Hence, number of pieces of chocolate left with Manju is 3.

The number of pieces of chocolate with Maniu

= \( \Large 1 - \left(\frac{1}{4}+\frac{1}{3}+\frac{1}{6}\right) \)

= \( \Large 1 - \left(\frac{3 + 4 + 2}{12}\right) \)

= \( \Large 1 - \frac{9}{12} = \frac{12 - 9}{12} = \frac{3}{12} \)

Hence, number of pieces of chocolate left with Manju is 3.

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