A) Only I |
B) Only II |
C) Both 1 and H |
D) Neither I nor II |
B) Only II |
Let the two-digit number be 10x + y.
Now, according to the question,
x + y = 10 ...(i)
and \( \Large \left(x+10y\right)+36 = \left(y+10x\right) \)
=> \( \Large -9y + 9x = 36 \)
=> \( \Large -y + x = 4 \) ...(ii)
On adding Eqs. (i) and (ii), we get
2x = 14 = x = 7
Therefore, x = 7 and y = 3
Therefore, Required number is 73.
So, the number is a multiple of a number.