X, Y and Z had taken a dinner together. The cost of the meal of Z was 20% more than that of Y and the cost of the meal of X was $$\Large \frac{5}{6}$$ as much as the cost of the meal of Z. If Y paid Rs.100, then what was the total amount that all the three of them had paid?
 A) Rs.285 B) Rs.300 C) Rs.355 D) 320

 D) 320

Given that,

The cost of meal of y = Rs.100

Now, according to the question,

The cost of the meal of z = 20% more than that of y

$$\Large \left(100 + \frac{20}{100} \times 100\right)= \left(100 + 20\right) = Rs.120$$

and the cost of the meal of x = $$\Large \frac{5}{6}$$ as much

as the cost of the meal of z

$$\Large \frac{5}{6} \times 120$$ = Rs.100

Therefore, Total amount that all the three of them has paid

= 100 + 120 + 100 = Rs.320

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