X, Y and Z had taken a dinner together. The cost of the meal of Z was 20% more than that of Y and the cost of the meal of X was \( \Large \frac{5}{6} \) as much as the cost of the meal of Z. If Y paid Rs.100, then what was the total amount that all the three of them had paid?
Correct Answer: Description for Correct answer:
Given that,
The cost of meal of y = Rs.100
Now, according to the question,
The cost of the meal of z = 20% more than that of y
\( \Large \left(100 + \frac{20}{100} \times 100\right)= \left(100 + 20\right) = Rs.120 \)
and the cost of the meal of x = \( \Large \frac{5}{6} \) as much
as the cost of the meal of z
\( \Large \frac{5}{6} \times 120 \) = Rs.100
Therefore, Total amount that all the three of them has paid
= 100 + 120 + 100 = Rs.320
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