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6 men can do a piece of work in 12 days while 8 women can do the same work in 18 days. The same work can be done by 18 children in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men have to complete remaining work in 1 day, then find the required number of men.


A) 36

B) 24

C) 18

D) Couldn't be determined

Correct Answer:
A) 36

Description for Correct answer:
\( \Large 6\times 12 \) men = \( \Large 8\times 18 \) women

= \( \Large 18\times 10 \) children

=> 12 men = 24 women = 30 children

=> 2 men = 4 women = 5 children

Now, 4 men + 12 women + 20 children

=4 men + 6 men + 8 men = 18 men

Time to do remaining work for 1 man

= \( \Large 16\times 12-18\times 2 \)=36 days

Required number of men to finish the work in 1 day = 36

Part of solved Time and work questions and answers : >> Aptitude >> Time and work




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