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A, B and C can do a piece of work individually in 8, 12 and 15 days, respectively. A and B start working but A quits after working for 2 days. After this, C joins B till the completion of work. In how many days will the work be completed?

A) \( \Large 5\frac{8}{9} \)days
B) \( \Large 4\frac{6}{7} \)days
C) \( \Large 6\frac{7}{13} \)days
D) \( \Large 3\frac{3}{4} \)days

Correct Answer:

A) \( \Large 5\frac{8}{9} \)days

Description for Correct answer:

Work done by A and B in 1 day

=\( \Large \frac{1}{8}+\frac{1}{12}=\frac{5}{24} \)

2 day's work of A and B = \( \Large \frac{10}{24} \)

After 2 day's A left the work

Remaining work = \( \Large 1-\frac{10}{24}=\frac{14}{24} \)

One day work of B and C together

= \( \Large \frac{1}{12}+\frac{1}{15}=\frac{9}{60} \)

So, the number of days required by B and C to finish work

= \( \Large \frac{14/24}{9/60} \)=\( \Large \frac{14}{24}\times {60}{9}=\frac{35}{9} \)

Total days to complete the work

= \( \Large 2+\frac{35}{9}=\frac{53}{9} \)=\( \Large 5\frac{8}{9} \) days.

Part of solved Time and work questions and answers : >> Aptitude >> Time and work

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