A) 12 |
B) 68 |
C) 72 |
D) 90 |
D) 90 |
Work done by A in 4 days = \( \Large \frac{4}{20}=\frac{1}{5} \)
Remaining work = \( \Large 1-\frac{1}{5}=\frac{4}{5} \)
Let C can working alone complete the work in x days.
According to the question,
\( \Large \frac{18}{30}+\frac{18}{x}=\frac{4}{5} \)
=> \( \Large 18(x+30)\times 5 \)=\( \Large 4\times 30x \)
=> 90x+2700=120x
=> 30x=2700
x=90 days