A) 40 h |
B) 30 h |
C) 50 h |
D) 30 h |
A) 40 h |
Let the leak empties the full tank in x h then
Part emptied in 1 h by leak = \( \Large \frac{1}{x} \)
Part filled by inlet in 1 h = \( \Large \frac{1}{20} \)
According to the question.
\( \Large \frac{1}{20} \)+\( \Large \frac{1}{x} \)=\( \Large \frac{1}{40} \)
Therefore, \( \Large \frac{1}{x} \) = \( \Large \frac{1}{40} \)-\( \Large \frac{1}{20} \)
= \( \Large \frac{1-2}{40} \)= \( \Large - \frac{1}{40} \)
[Negative sign indicates emptying]
Clearly, leak will empty the full tank in 40 h