Two pipes P and Q can fill a cistern in 12 and 15 min, respectively. If both are opened together and at the end of 3 min, the first is closed. How much longer will the cistern take to fill?
Correct Answer: A) \( \Large 8\frac{1}{4} \) |
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Description for Correct answer:
Part filled by pipe P in 1 min = \( \Large \frac{1}{12} \)
Part filled by pipe Q in 1 min = \( \Large \frac{1}{15} \)
Part filled by both pipes in 1 min
= \( \Large \frac{1}{12} \)+ \( \Large \frac{1}{15} \)= \( \Large \frac{5+4}{60} \)= \( \Large \frac{9}{60} \)
Now, part filled by both pipes in 3 min
= \( \Large \frac{3 \times 9}{60}=\frac{27}{60}=\frac{9}{20} \)
Remaining part = \( \Large 1 - \frac{9}{20} = \frac{11}{20} \)
Let the remaining part is filled by pipe Q in x min.
Then, \( \Large x \times \frac{1}{15} = \frac{11}{20} \)
\( \Large x = \frac{15 \times 11}{20} = \frac{3 \times 11}{4}
= \frac{33}{4} = 8\frac{1}{4} min \)
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