Topics

A) \( \Large 9\frac{3}{13} \) h |

B) \( \Large 9\frac{4}{13} \) h |

C) \( \Large 9\frac{7}{13} \) h |

D) \( \Large 9\frac{9}{13} \) h |

Correct Answer:

A) \( \Large 9\frac{3}{13} \) h |

Description for Correct answer:

Part filled by A in 1 min = \( \Large \frac{1}{30} \)

Part filled by B in 1 min = \( \Large \frac{1}{10} \)

Part emptied by C in 1 min = \( \Large \frac{1}{40} \)

Net part filled in 1 h by (A + B + C)

= \( \Large \left(\frac{1}{30}+\frac{1}{10}-\frac{1}{40}\right) \)

= \( \Large \frac{4+12-3}{120} = \frac{13}{120} \)

Therefore, Required time to fill the tank = \( \Large \frac{120}{13} \)h = \( \Large 9\frac{3}{13} \) h

Part filled by A in 1 min = \( \Large \frac{1}{30} \)

Part filled by B in 1 min = \( \Large \frac{1}{10} \)

Part emptied by C in 1 min = \( \Large \frac{1}{40} \)

Net part filled in 1 h by (A + B + C)

= \( \Large \left(\frac{1}{30}+\frac{1}{10}-\frac{1}{40}\right) \)

= \( \Large \frac{4+12-3}{120} = \frac{13}{120} \)

Therefore, Required time to fill the tank = \( \Large \frac{120}{13} \)h = \( \Large 9\frac{3}{13} \) h

Part of solved Pipes and Cisterns questions and answers : >> Aptitude >> Pipes and Cisterns

Comments

Similar Questions