A) \( \Large 3\frac{3}{14} \) h |
B) \( \Large 2\frac{1}{2} \) h |
C) \( \Large 3\frac{9}{14} \) h |
D) \( \Large 2\frac{1}{14} \) h |
B) \( \Large 2\frac{1}{2} \) h |
Part filled by A in 1 h = \( \Large \frac{1}{5} \)
Part filled by B in 1 h = \( \Large \frac{1}{6} \)
Part filled by C in 1 h = \( \Large \frac{1}{30} \)
Net part filled by (A + B + C) in 1 h
= \( \Large \left(\frac{1}{5}+\frac{1}{6}+\frac{1}{30}\right) \)
= \( \Large \frac{6+5+1}{30} = \frac{12}{30} \) = \( \Large \frac{2}{5} \)
Therefore, Required time to fill the tank = \( \Large \frac{5}{2} \)h = \( \Large 2\frac{1}{2} \) h