If 10 spiders can catch 10 flies in 10 min, then how many flies can 200 spiders catch in 200 min?
Correct Answer: Description for Correct answer:
Let the required number of files be
More spiders, More flies (Direct proportion)
More time, More flies (Direct Proportion)
Spiders 10 : 200 )
Time 10 : 200 ) :: 10 : x
Therefore, \( \Large \left(10 \times 10 \times x\right) = \left(200 \times 200 \times 10\right) \)
Therefore, x = \( \Large \frac{200 \times 200 \times 10}{10 \times 10} \) = 4000 files
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