If n is a whole number greater than 1, then \( \Large n^{2}(n^{2}-1) \) is always divisible by
Correct Answer: Description for Correct answer:
If n greater than 1,then \( \Large n^{2}(n^{2}-1) \)
always divisible by 12.
Illustration 1
Put n = 2, then \( \Large n^{2}(n^{2}-1) \)=\( \Large (2^{2})(2^{2}-1) \)
= \( \Large 4\times 3 \)=12
Illustration 2 Now, put n = 3, then
\( \Large n^{2}(n^{2}-1) \)= \( \Large (3)^{2}(3^{2}-1) \)=\( \Large 9\times 8 \) = 72
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