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A student walks from his house \( \Large 2 \frac{1}{2} \) % km/h and reaches his school late by 6 min. Next day, he increases his speed by 1 km/h and reaches 6 min before school time. How far is the school from his house?

A) \( \Large \frac{5}{4} km \)
B) \( \Large \frac{7}{4} km \)
C) \( \Large \frac{9}{4} km\)
D) \( \Large \frac{11}{4} km\)

Correct Answer:


B) \( \Large \frac{7}{4} km \)

Description for Correct answer:

Let the required distance = x

According to the question,

Speed = 5/2

After increasing speed by 1 km.hr = (5/2) + 1 = 7/2

\( \Large \frac{x}{\frac{5}{2}} - \frac{x}{\frac{7}{2}} = \frac{12}{60} \)

(difference between two times = 6 + 6 = 12 min)

=> \( \Large \frac{2x}{5} - \frac{2x}{7} = \frac{1}{5} \)

=> 14x - 10x = 7

=> 4x = 7

=> \( \Large x = \frac{7}{4} km \)

Part of solved Time and Distance questions and answers : >> Aptitude >> Time and Distance

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Similar Questions

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