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A is twice as fast as B and B is thrice as fast as C. The journey covered by C in 56 min will be covered by A in

A) \( \Large 5 \frac{1}{3} min \)
B) \( \Large 2 \frac{1}{3} min \)
C) \( \Large 7 \frac{1}{3} min \)
D) \( \Large 9 \frac{1}{3} min \)

Correct Answer:




D) \( \Large 9 \frac{1}{3} min \)

Description for Correct answer:

Let time taken by A = y

Let speed of C = x

Then, speed of B = 3x

Speed of A = 6x

Now, ratio of speeds of A and C

= Ratio of time taken by C and A

6x : x = 56 : y => \( \Large \frac{6x}{x} = \frac{56}{y} \)

\( \Large y = \frac{56}{6} = 9\frac{2}{6} = 9\frac{1}{3} min \)

Part of solved Time and Distance questions and answers : >> Aptitude >> Time and Distance

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