A thief is spotted by a policeman from a distance of 200 m. When the policeman starts chasing, the thief also starts running. If the speed of the thief be 16 km/h and that of the policeman be 20 km/h, how far the thief will have run before he is overtaken?


A) 800 m

B) 850 m

C) 700 m

D) 650 m

Correct Answer:
A) 800 m

Description for Correct answer:

Relative speed of policeman

\( \Large \left(20-16\right) \times \frac{5}{18} = \frac{10}{9} m/s \)

To catch the thief, the policeman has to gain 200 m.

Time taken to gain 200 m = \( \Large \frac{200 \times 9}{10} = 180 s \)

Actual distance covered by policeman in \( \Large 180 s = 180 \times \frac{50}{9} = 1000 m \)

Therefore, Distance covered by the thief

= 1000 - 200 = 800 m


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