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The angle elevation of a tower from a distance 100 mtr. from its foot is 30o . Then the height of the tower is :


A) \( \Large \frac{50}{\sqrt{3}}mtr \)

B) \( \Large 50\sqrt{3} mtr \)

C) \( \Large \frac{100}{\sqrt{3}} mtr \)

D) \( \Large 100\sqrt{3} mtr \)

Correct Answer:
C) \( \Large \frac{100}{\sqrt{3}} mtr \)

Description for Correct answer:



Let height of tower = x

Therefore, \( tan 30 ^{\circ} \) = \( \frac{x}{100} \)

x = \( 100 \times tan 30 ^{\circ} = \frac{100}{\sqrt{3}}mtr \)


Part of solved SSC Practice test(1) questions and answers : Exams >> SSC Exams >> SSC Practice test(1)




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