Find the square root of:
\( \Large  \frac{ \left(0.064-0.008\right) \left(0.16-0.04\right) }{ \left(0.16+0.08+0.04\right) \left(0.4+0.2\right)^{3} } \)


A) 3

B) \( \Large \frac{3}{2} \)

C) \( \Large \frac{2}{3} \)

D) \( \Large \frac{1}{3} \)

Correct Answer:
D) \( \Large \frac{1}{3} \)

Description for Correct answer:

To find :

\( \Large  \sqrt{\frac{ \left(0.064-0.008\right) \left(0.16-0.04\right) }{ \left(0.16+0.08+0.04\right) \left(0.4+0.2\right)^{3} }} \)

Let x = 0.4 ; y = 0.2

\( \Large  \sqrt\frac{ \left(x^{3}-y^{3}\right) \left(x^{2}-y^{2}\right) }{ \left(x^{2}+xy+y^{2}\right) \left(x+y\right)^{3} } \)

since \( \Large  \left(x^{3}-y^{3}\right) = \left(x-y\right) \left(x^{2}+xy+y^{2}\right) \)

Therefore, \( \Large  \sqrt \frac{ \left(x-y\right) \left(x+y\right) \left(x-y\right) }{ \left(x+y\right)^{3} } =  \frac{ \left(x-y\right)^{2} }{ \left(x+y\right)^{2} } \)

= \( \Large  \frac{x-y}{x+y} = \frac{0.4-0.2}{0.4+0.02} = \frac{1}{3} \)


Part of solved SSC Practice test(1) questions and answers : Exams >> SSC Exams >> SSC Practice test(1)








Comments

No comments available




Similar Questions
1). The angle elevation of a tower from a distance 100 mtr. from its foot is 30o . Then the height of the tower is :
A). \( \Large \frac{50}{\sqrt{3}}mtr \)
B). \( \Large 50\sqrt{3} mtr \)
C). \( \Large \frac{100}{\sqrt{3}} mtr \)
D). \( \Large 100\sqrt{3} mtr \)
-- View Answer
2). A sum of money lent out at simple interest amounts to Rs.720 after 2 years and Rs.1020 after a further period of 5 years. Find the principal.
A). Rs.1740
B). Rs.120
C). Rs.6000
D). Rs.600
-- View Answer
3). A can do a work in 10 days and B in 20 days. If they together work on it for 5 days, then the fraction of the work that is left is :
A). \( \Large \frac{1}{4} \)
B). \( \Large \frac{3}{4} \)
C). \( \Large \frac{3}{20} \)
D). \( \Large \frac{4}{3} \)
-- View Answer
4). A man spends 75% of his income. His income is increased by 20% and he increased his expenditure by 10%. His savings are increased by:
A). \( \Large 37\frac{1}{2}\% \)
B). 0.5
C). 0.1
D). 0.25
-- View Answer
5). Pipe A can fill a tani in 4 hours and Pipe B can fill it in 6 hours. If they are opened on alternate opurs ad if pipe A is opene first then in how many hours, the tank shall be full?
A). \( \Large 3\frac{1}{2} \)
B). \( \Large 3\frac{1}{4} \)
C). \( \Large 4\frac{1}{2} \)
D). \( \Large 4\frac{21}{3} \)
-- View Answer


6). A shopkeeper gains 17% after allowing a discount of 10% on the marked price of an article. Find his profit percent if the article is sold at marked price allowing no discount.
A). 0.3
B). 0.37
C). 0.23
D). 0.27
-- View Answer
7). ABC is a triangle and the sides AB, BC and CA are produced to E, F and G respectively. If \( \angle CBE = \angle ACF = 130 ^{\circ} \), then the value of \( \angle GAB \) is
A). \( 130 ^{\circ} \)
B). \( 90 ^{\circ} \)
C). \( 100 ^{\circ} \)
D). \( 80 ^{\circ} \)
-- View Answer
8). A person of height 6 ft. wants to pluck a fruit which is on a 26/3 ft. high tree. lf the person is standing 8/ 3 ft. away from the base of the tree, then at what angle should he throw a stone so that, it hits the fruit?
A). \( 60 ^{\circ} \)
B). \( 75 ^{\circ} \)
C). \( 30 ^{\circ} \)
D). \( 45 ^{\circ} \)
-- View Answer
9). Cost price of 100 books is equal to the selling price of 60 books. The gain percentage or loss percentage is :
A). \( \Large 66\frac{2}{3} \%\)
B). 0.67
C). 0.66
D). \( \Large 66\frac{2}{3} \%\)
-- View Answer
10). lf the cube root of 79507 is 43, then the value of

\( \Large 3\sqrt{79.5807}+3\sqrt{0.079507}+3\sqrt{0.000079507} is \)
A). 0.4773
B). 477.3
C). 4.773
D). 47.73
-- View Answer