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In a group of 6 boys and 4 girls 4 children are to be selected. In how many different ways can they be selected such that at least one boy should be there?

A) 159
B) 205
C) 194
D) 209

Correct Answer:




D) 209

Description for Correct answer:
No. of ways

= \( \Large 6_{C_{1}} + \left(6_{C_{3}} \times 4_{C_{1}}\right) + \left(6_{C_{2}} \times 4_{C_{2}}\right) + \left(6_{C_{1}} \times 4_{C_{2}}\right) \)

= \( \Large 15 + \left(20 \times 4\right) + \left(15 \times 6\right) + \left(6 \times 4\right) \)

= 15 + 80 + 9 + 24 = 209

Part of solved Permutation and combination questions and answers : >> Aptitude >> Permutation and combination

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