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4 boys and three girls are to be seated in a row in such a way that no two boys sit adjacent to each other. In how many different ways can it be done?

A) 5040
B) 30
C) 144
D) 72

Correct Answer:



C) 144

Description for Correct answer:
3 girls can be seated in a row in 3! ways.

Now, in the 4 gaps 4 BGBGBGB boys can be seated in 4! ways

Hence, the number of ways in which no two boys sit adjacent to each other

= \( \Large 3! \times 4! = 6 \times 24 = 144 \)

Part of solved Permutation and combination questions and answers : >> Aptitude >> Permutation and combination

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