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Two girls and 4 boys are to be seated in a row in such a way that the girls do not sit together. In how many different ways can it be done?

A) 720
B) 480
C) 360
D) 240

Correct Answer:


B) 480

Description for Correct answer:
4 boys can be seated in a row in \( \Large ^{4}P_{4} \) = 4! ways

Now in the 5 gaps 2 girls can be arranged in \( \Large ^{5}P_{2} \) ways

Hence, the number of ways in which no two girls sit together

= \( \Large 4! \times ^{5}P_{2} = 4 \times 3 \times 2 \times 5 \times 4 \)

= 480

Part of solved Permutation and combination questions and answers : >> Aptitude >> Permutation and combination

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