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In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer

I. \( \Large x^{2} \) - 16 = 0

II. \( \Large y^{2} \) - 9y + 20 = 0


A) x > y

B) x \( \Large \geq \) y

C) x < y

D) x \( \Large \leq \) y

Correct Answer:
D) x \( \Large \leq \) y

Description for Correct answer:
I. \( \Large x^{2} \) = 16

=> x = \( \Large \pm \)4

II. \( \Large y^{2} \) - 9y + 20 = 0

=> \( \Large y^{2} \) - 4y - 5y + 20 = 0

=> y ( y - 4 ) - 5 ( y - 4 ) = 0

=> ( y - 5 )( y - 4 ) = 0

\( \Large \therefore \) y = 5 or 4

Clearly, x \( \Large \leq \) y

Part of solved Linear Equations questions and answers : >> Aptitude >> Linear Equations




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