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The highest score in an innings was \( \Large \frac{3}{11} \) of the total score and the next highest was \( \Large \frac{3}{11} \) of the remainder. If the scores differ by 18, find the total score.
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A) 244 |
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B) 242 |
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C) 294 |
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D) 255 |
Correct Answer:
| B) 242 |
Description for Correct answer:
Let total score = x.
Then, the highest score = \( \Large \frac{3x}{11} \)
Remainder = \( \Large \left(x-\frac{3x}{11}\right)=\frac{8x}{11} \)
Next highest score = \( \Large \frac{3}{11}\ of\ \frac{8x}{11}=\frac{24x}{121} \)
According to the question,
\( \Large \frac{3x}{11}-\frac{24x}{121}=18 \)
=>\( \Large 33x-24x = 18 \times 121 \)
\( \Large 9x = 18 \times 121 \)
Therefore, \( \Large x=\frac{18 \times 121}{9} \)=242
Let total score = x.
Then, the highest score = \( \Large \frac{3x}{11} \)
Remainder = \( \Large \left(x-\frac{3x}{11}\right)=\frac{8x}{11} \)
Next highest score = \( \Large \frac{3}{11}\ of\ \frac{8x}{11}=\frac{24x}{121} \)
According to the question,
\( \Large \frac{3x}{11}-\frac{24x}{121}=18 \)
=>\( \Large 33x-24x = 18 \times 121 \)
\( \Large 9x = 18 \times 121 \)
Therefore, \( \Large x=\frac{18 \times 121}{9} \)=242
Part of solved Simplification questions and answers : >> Elementary Mathematics >> Simplification
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