From a group of men and women, 15 women leave from it. Then, there are 2 men for each women. After this, 45 men leave. Then, there are 5 women for each men. Find the double of the number of women in the beginning.
Correct Answer: Description for Correct answer:
Let at present, there are x men, then number of women = 5x.
Before the men had left number of men = x +45 and
number of women = 5x
Therefore, \( \Large x+45 = 2 \times 5x \)
=> \( \Large 9x = 45 \)
Therefore, \( \Large x = \frac{45}{9} \) = 5
Hence, number of women in the beginning = \( \Large 5x+15=5 \times 5+15 \)
=25 + 15 = 40
Therefore, Double of the women = \( \Large 40 \times 2 \) = 80
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