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The equation of line parallel to lines \( \Large L_{1}=x+2y-5=0\ and\ x+2y+9=0 \) and dividing the distance between \( \Large L_{1} \) and \( \Large L_{2} \) in the ratio 1 : 6 (internally) is:


A) \( \Large x+2y-3=0 \)

B) \( \Large x+2y+2=0 \)

C) \( \Large x+2y+7=0 \)

D) none of these

Correct Answer:
A) \( \Large x+2y-3=0 \)

Description for Correct answer:

Let line be \( \Large x+2y+n=0 \)

\( \Large n=\frac{-5 \times 6+1 \times 9}{7}=-3 \) \( \Large \    Here \   n = \frac{mc_{2}+nc_{1}}{m+n} \)

So, required line is \( \Large x+2y-3=0 \).


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