A) \( \Large a=-1,\ b=-1,\ c=2 \) |
B) \( \Large a=1,\ b=-1,\ c=0 \) |
C) \( \Large a=-1,\ b=-1,\ c=0 \) |
D) \( \Large a=1,\ b=1,\ c=1 \) |
B) \( \Large a=1,\ b=-1,\ c=0 \) |
Since, the co-ordinates of three vertices A, B and C are \( \Large \left(\frac{5}{3},\ -\frac{4}{3}\right),\ \left(0,\ 0\right)\ and\ \left(-\frac{2}{3},\ \frac{7}{3}\right) \) respectively. Also the mid point of AC is \( \Large \left(\frac{1}{2},\ \frac{1}{2}\right) \).
Therefore, the equation of line passing through \( \Large \left(\frac{1}{2},\ \frac{1}{2}\right) \) and \( \Large \left(0,\ 0\right) \) is given by \( \Large x-y=0 \), which is the required equation of another diagonal. \( \Large a=1,\ b=-1\ and\ c=0 \)