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Equation to the straight line cutting of an intercept from the negative direction of the axis of y and inclined at \( \Large 30 ^{\circ} \) to the positive direction of axis of x is:


A) \( \Large y+x-\sqrt{3}=0 \)

B) \( \Large y-x+2=0 \)

C) \( \Large y-\sqrt{3}x-2=0 \)

D) \( \Large \sqrt{3}y-x+2\sqrt{3}=0 \)

Correct Answer:
D) \( \Large \sqrt{3}y-x+2\sqrt{3}=0 \)

Description for Correct answer:
Let the equation of line is y = mx + C \( \Large m = tan 30 ^{\circ} = \frac{1}{\sqrt{3}} \) and c = -2 [Because, It is intercepted in negative axes of y with an angle of \( \Large 30 ^{\circ} \)] The required line \( \Large y = \frac{x}{\sqrt{3}} - 2 => \sqrt{3}y - x + 2\sqrt{3} = 0 \)

Part of solved Straight lines questions and answers : >> Elementary Mathematics >> Straight lines




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