If the \( \Large \angle \theta \) is acute, then the acute angle between \( \Large x^{2} \left(\cos \theta -\sin \theta \right)+2xy \cos \theta +y^{2} \left(\cos \theta +\sin \theta \right)=0 \) is
Correct Answer: Description for Correct answer:
Comparing the given equation, we get
\( \Large a=\cos \theta - \sin \theta ,\ b=\cos \theta + \sin \theta ,\ h=\cos \theta \)
\( \Large tan\phi =\frac{2\sqrt{h^{2}-ab}}{a+b} \)
=>\( \Large \tan \phi = \frac{2\sqrt{\cos^{2} \theta - \left(\cos^{2} \theta - \sin^{2} \theta \right) }}{\cos \theta - \sin \theta +\cos \theta +\sin \theta } = \frac{2\sin \theta }{2\cos \theta } \)
=> \( \Large \tan \phi = \tan \theta => \phi = 0 \)
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