If the angle of elevation of a tower from two distant points a and b (a > b) from its foot and In the same straight line and on the same side of it are \( \Large 30 ^{\circ} \) and \( \Large 60 ^{\circ} \), then the height of the tower is


A) \( \Large \sqrt{\frac{a}{b}} \)

B) \( \Large \sqrt{a+b} \)

C) \( \Large \sqrt{ab} \)

D) \( \Large \sqrt{a-b} \)

Correct Answer:
C) \( \Large \sqrt{ab} \)

Description for Correct answer:

Let AB be the tower.

Where, AB = h m



In \( \Large \triangle ABC, \tan 60 ^{\circ} =\frac{h}{b} \) ...(i)

In \( \Large \triangle ABD, \tan 30 ^{\circ} =\frac{h}{a} \) ...(ii)

On multiplying Eqs. (i) and (ii), we get

\( \Large \tan 60 ^{\circ} \tan 30 ^{\circ} = \frac{h^{2}}{ab} \)

=> \( \Large \sqrt{3} \times \frac{1}{\sqrt{3}}=\frac{h^{2}}{ab} => h^{2} = ab \)

\( \Large \therefore h = \sqrt{ab} \)


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