A) \( \Large - \alpha ,\ - \beta \) |
B) \( \Large \alpha ,\ \frac{1}{ \beta } \) |
C) \( \Large \frac{1}{ \alpha },\ \frac{1}{ \beta } \) |
D) none of these |
C) \( \Large \frac{1}{ \alpha },\ \frac{1}{ \beta } \) |
Since \( \Large \alpha \) and \( \Large \beta \) are the roots by \( \Large ax^{2}+bx+c=0 \)
=> \( \Large \alpha + \beta \) = \( \Large -\frac{b}{c} \) and \( \Large \alpha \beta = \frac{c}{a} \)
Let the roots of \( \Large cx^{2}+bx+a=0 \) be \( \Large \alpha' \), \( \Large \beta' \) then
\( \Large \alpha' \) + \( \Large \beta' \) = \( \Large -\frac{b}{c} \) and \( \Large \alpha . \beta = \frac{a}{c} \)
Now, \( \Large \frac{ \alpha + \beta }{ \alpha \beta }=\frac{\frac{-b}{a}}{\frac{c}{a}}=\frac{-b}{c} \)
=> \( \Large \frac{1}{ \alpha }+\frac{1}{ \beta }= \alpha' + \beta' \)
Hence, \( \Large \alpha' \) = \( \Large \frac{1}{ \alpha } \) and \( \Large \beta' \) = \( \Large \frac{1}{ \beta } \)