A man standing in one corner of a square football field observes that the angle subtended by a pole in the corner just diagonally opposite to this corner is \( \Large 60 ^{\circ} \). When he retires 80 m from the corner, along the same straight line, he finds the angle to be \( \Large 30 ^{\circ} \). The length of the field is


A) 20 m

B) \( \Large 40\sqrt{2} \) m

C) 40 m

D) \( \Large 20\sqrt{2} \) m

Correct Answer:
C) 40 m

Description for Correct answer:

From the figure,

Let the length of football field = l m



Height of the pole = x m

Therefore, In \( \Large \triangle ABC, \tan 60 =\frac{x}{l} \)

\( \Large \sqrt{3}=\frac{x}{l}; x=\sqrt{3}l \)

Now, in \( \Large \triangle ABD \)

\( \Large \tan 30 ^{\circ} =\frac{x}{l+80} => \frac{1}{\sqrt{3}} = \frac{x}{l+80} \)

\( \Large l + 80 = \sqrt{3}x \)

Now, from Eq. (i), we get

\( \Large l + 80 = \sqrt{3} \left(\sqrt{3} l\right) \)

=> \( \Large l + 80 = 3l => 80 = 3l - l \)

\( \Large \therefore\ l = \frac{80}{2} = 40 m \)


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