A) 150 |
B) 216 |
C) 316 |
D) 450 |
B) 216 |
Given, \( \Large \sqrt{10 + \sqrt[3]{x}} = 4 \)
On squaring both sides, we get
\( \Large 10 + \sqrt[3]{x} = 16 \)
=> \( \Large \sqrt[3]{x} = 6 \)
Now, cubic on both sides, we get
\( \Large x = \left(6\right)^{3} = 216 \)